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Wednesday, January 27, 2010

Base 52

The following SAS program is submitted:

data work.empsalary;
set work.people (in = inemp) work.money (in = insal);
if insal and inemp;
run;

The SAS data set WORK.PEOPLE has 5 observations, and the data set WORK.MONEY has 7 observations.

How many observations will the data set WORK.EMPSALARY contain?
A. 0
B. 5
C. 7
D. 12

10 comments:

SASGuru said...

Answer: A
Since there is no BY statement..this is an example of concatenation…there is no match between each of the datasets…therefore 0 records in the output dataset

siva said...

Thanks for Answer SASGuru....

Reebok said...

wait a minute! shouldn't there be 12? i thought concatenation would append one file over the other.

Reebok said...

nevermind. the "if insal and inemp;" statement create no matches, therefore no records.

Amit Rathore said...

In concatenation...SAS reads 1 dataset first and then the second. So if you specify IN=variable for both datasets and wants to know that whether both the dataset contributed to the current observation seems to be a false idea bcoz 1 dataset get reads first and then the second.So no matches.
Hence answer is A.

Stevina Rumao said...

YES Amit that's the right explanation of the answer

Anonymous said...

This is not just a SET statement. It has a IN=variable for both datasets. BUT there is no by statement. So the answer is 0 match. Answer is A

Unknown said...

Not enough info given... if you run




data test;
input obs name $ level;
cards;
1 Frank 1
2 Joan 2
3 Sui 2
4 Jose 3
5 Burt 4
6 Kelly .
7 Juan 1
;
run;
data test2;
input obs name $ level;
cards;
1 Frank 1
2 Joan 2
3 Sui 2
4 Jose 3
;
run;

data mergetest;
merge test(in=a) test2(in=b);
if a and b;
run;

then there are 4 obs in the merged set.

We are not told in the question that the two sets do/do not have matching rows.

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Unknown said...

hi unknown run your code again this time without the merge and replace with set !

This is not a merge question it is a concatenation

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